OneAndOne Basketball Shots
Theoretical Probabilities Using Area Model
You should have completed and understood this worksheet. Be
sure to see Mr. Beaty if you have any questions about
the work here.
60% Shooter (60% = 60/100 = 6/10
= .6) 
p(0) = .4
p(1) = .24
p(2) = .36
Most likely
Outcome = 0
Average points
per trip = .96 


40% Shooter (40% = 40/100 = 4/10
= .4) 
p(0) = .6
p(1) = .24
p(2) = .16
Most likely
Outcome = 0
Average points
per trip = .56 


20% Shooter (20% = 20/100 = 2/10
= .2) 
p(0) = .8
p(1) = .16
p(2) = .04
Most likely
Outcome = 0
Average points
per trip = .24 


80% Shooter (80% = 80/100 = 8/10
= .8) 
p(0) = .2
p(1) = .16
p(2) = .64
Most likely
Outcome = 2
Average points
per trip = 1.44 


Make sure YOU determined and understand the results above. Then copy
the results in the table below so that you can look for easy patterns in the
numbers. This is why you will be able to answer quiz question easily and get
them all correct.
Summary 
Shooter's
Probability 
Theoretical Probabilities 
Average points
per trip 
0 points 
1 point 
2 points 
20% = 2/10 = .2 
.8 
.16 
.04 
.24 
40% = 4/10 = .4 
.6 
.24 
.16 
.56 
60% = 6/10 = .6 
.4 
.24 
.36 
.96 
80% = 8/10 = .8 
.2 
.16 
.64 
1.44 
Below are the patterns we found in the numbers
above. They are expressed as algebraic expressions (easy to remember and
use). Be sure you see how to discover them in the numbers above and you
learn them and how to use them for a quiz. 
p 
1p 
p(1p) 
p^{2} 
p + p^{2} 
After studying the above, be sure you paractice using your formulae
correctly. Try to answer P(0), P(1), P(2), and the average points per trip for
different shooters. Try a 50% shooter, a 75% shooter, and a 36% shooter. Try
others and check with friends to see if you all get the same answers.